SSC CGL QUANT QUIZ -5

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Question 1:

Oil equal to $12 \%$ of the weight of ground nut is extracted in a mill. The matter left after extraction is sold as cattle feed at the rate of Rs. $14 \frac{1}{2} / \mathrm{kg}$. The groundnuts are bought at Rs.18/kg. The processing cost is Rs.1.6/kg. At approximately what price (Rs per kg) should the oil be sold to earn $20 \%$ profit on total costs (Total cost $=$ Cost of groundnuts and processing costs)?

Question 2:

Find the simplified value of $\frac{(0.64+0.36)^{2}-(0.64-0.36)^{2}}{2 \times 0.64 \times 0.36}$

Question 3:

How many small solid spheres of radius $5 \mathrm{~mm}$ can be made from a solid metallic cone of base radius $21 \mathrm{~cm}$ and height of $40 \mathrm{~cm}$?

Question 4:

The average weight of the 9 persons in boat is increased by $1 \frac{1}{3} \mathrm{~kg}$ when one of the crew of weight $60 \mathrm{~kg}$ is replaced by a new person. The weight of new person is:

Question 5:

$\mathrm{PQ}$ and $\mathrm{PR}$ are tangents to a circle and $\mathrm{QR}$ is a chord, $\mathrm{PQ}=41 \mathrm{~cm}$ and $\mathrm{QR}=18 \mathrm{~cm}$, then find radius of the circle.

Question 6:

The base of right pyramid is a equilateral triangle of side $4 \mathrm{~cm}$. The height of the pyramid is half of its slant height. Its volume is:

Question 7:

There are 47 Students in a mess. If number of students increases by 9 , the expenses of the mess increases by Rs. 77 per day while the average expenditure per head decreases by Rs.2. What is the original expenditure (in rupees) of the mess?

Question 8:

The average of 12 number is 39 . The average of last 5 number is 35 , and that of the first four number is 40 . The fifth number is 10 less than the sixth number and 7 more than the seventh number. The average of the fifth and sixth number is:

Question 9:

Amount received after 3 years at $10 \%$ per annum compound interest is Rs. 15,972. What was the Principal? (in Rs.)

Question 10:

In $\mathrm{a}$ triangle $\mathrm{ABC} \ \; \mathrm{b}=4$ and $\frac{\cos A}{a}=\frac{\cos B}{b}=\frac{\cos C}{c}$ then area of triangle $\mathrm{ABC}$ is.