CAT QUANT NUMBER SYSTEM 9

शेष ज्ञात करें जब $\left(3^{41} +7^{ 41}\right)$  को 13 से विभाजित किया जाता है

In a division problem, product of quotient and the remainder is 24 while their sum is 10 . If the divisor is 5 then dividend is :

Let $n !=1 \times 2 \times 3 \times \ldots \times n$ for integler $n$ greater than or equal to $1 .$ If $P=1 !+(2 \times 2 !)+(3 \times 3 !)+\ldots . .+(12 \times 12 !)$, then $(P+3)$ when divided by $13 !$ Leaves a remainder of:

 $\left(29^{ 29}\right)^{29} $ को 9 से विभाजित करने पर शेषफल क्या होगा 

Which least natural number when added to $7^{\wedge} 84$ gives a resulting number that is divisible by 11

यदि $\mathrm{N}=\left(24^{3}+25^{3}+26^{3}+27^{3}\right)$, तो $\mathrm{N}$ को 102 से विभाजित करने पर शेषफल क्या होगा?

Find the remainder when $(7 ! x 6 !+8 ! x 7 !)$ is divided by $9 !$