DELHI POLICE DRIVER SPEED TIME AND DISTANCE QUANT QUIZ-3

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Question 1:

A train travels $600 \mathrm{~km}$ in 5 hours and the next $900 \mathrm{~km}$ in 10 hours. What is the average speed of the train?

Question 2:

A bike travelling at an average speed of $120$ $\mathrm{km} / \mathrm{h}$ takes $7.5$ minutes to travel a certain distance. By how much should it increase its speed (in $\mathrm{km} / \mathrm{h}$ ) to travel the same distance in 6 minutes.

Question 3:

The ratio between the speeds of two trains is 4: 5. If the second train runs 800 km in 8 hours, then what is the speed of the first train?

Question 4:

A motor car goes from Mumbai to Pune at a speed of 20 km/h and comes back from there at a speed of 30 km/h. What is the average speed of the car for the whole journey?

Question 5:

If Anita walks a certain distance at 13km/hr instead of 10km /hr, she would walk 30km more. The actual distance travelled by her is :

Question 6:

Rachit beats suchit by 40 metre or 20 second in a 1000 metre race. Find the time taken by Rachit to complete the race?

Question 7:

With average speed of 40 km/h a train reaches its destination in time. If it goes with an average speed of 35 km/h, it is late by 15 minutes. The total journey is: 

Question 8:

A train crosses a pole in $12 \mathrm{sec}$ and crosses a boy sitting in another train coming from the opposite direction in $4 \mathrm{sec}$. If the speed of another train is $108 \mathrm{~km} / \mathrm{hr}$ then find the length of first train.

Question 9:

Two trains of equal length take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?

Question 10:

A bus covers a certain distance in 4 hour. If speed of bus reduced to $40 \mathrm{~km} / \mathrm{h}$, then it will take 1 hour more to cover the same distance. Then find the difference (in hours) between usual time and time taken by bus after increasing the usual speed by $100 \%$.