BIHAR CGL PRE SIMPLIFICATION QUIZ - 29

Solve:

$ \frac{7 \frac{1}{2} \div 4 \frac{2}{7} \text { of } \frac{3}{5}+\left(4 \frac{5}{8}-3 \frac{2}{7}\right) \div \frac{15}{14}}{18 \div 6 \text { of } 4+4 \times 5 \div 3 \text { of } 25} $

Simplify the following :

$\frac{\sqrt{7}-\sqrt{5}}{\sqrt{7}+\sqrt{5}}+\sqrt{35}$

If $m$ and $n$ be the two rational numbers such that $m^{n}=25$, then the value of $n^{m}$ is :

Solve the given equation -

$\left(\frac{7}{16} \div \frac{1}{2}\right.$ of $\left.\frac{1}{5}\right) \times \frac{4}{5}-\frac{1}{3} \times \frac{5}{8} \times 2+\frac{3}{4}$

The value of $3 \frac{1}{2}\left[2 \frac{1}{4} \div\left\{1 \frac{1}{4}-\frac{1}{2}\left(1 \frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\right\}\right]$ is:

Simplify:

$\frac{\left[3 \frac{1}{4}+\left\{1 \frac{1}{4}-\frac{1}{2}\left(2 \frac{1}{2}-\frac{1}{4}-\frac{1}{6}\right)\right\}\right]}{\frac{1}{2} \text { of } 4 \frac{1}{3}}$

$\frac{\sqrt[]{1024}}{\sqrt{16}} \div \sqrt{\frac{1225}{25}} \times \sqrt[]{625}$ is equal to:

There is set of 3 numbers which is in ascending order. Mean of 2 two numbers is 64 and mean of last 2 numbers is 30. Find out the range of this set.

Direction : What should come in place of question mark (?) in the following question?

$29 \frac{2}{5}+7 \frac{3}{5}-12 \frac{3}{10}=?-2 \frac{13}{15}$