Free Practice Questions for Reasoning Subject, Attempt Now!

As per given equation;

483 × 23 + 93 - 16 ÷ 4 = 50

After interchanging the signs and applying option (1),( ÷ and × ) in the given equation;

483 ÷ 23 + 93 - 16 × 4 = 50

Apply BODMAS,

21 + 93 - 64 = 50

114 - 64 = 50

50 = 50

L.H.S = R.H.S

Hence, option (1) is the correct answer.

As per given information;

14 -7 ÷ 2 + 9 × 3 = 3

After interchanging the signs of option (4),( ÷ and × ) in the given equation;

14 -7 × 2 + 9 ÷ 3 = 3

Apply BODMAS;

= 14 - 14 + 3 = 3

= 17 - 14 = 3

= 3 = 3

L.H.S = R.H.S

Hence, option (4) is the correct answer.

Given,

$125-5÷15+$ $2\times 4+3$

After changing sign,

$125÷5+15\times 2-4\times 3$

$=25+30-12$

$=25+18=43$

Hence, option (3) is correct answer,

 64+16-22÷11×5=70

64+16-2×5

64+16-10

80-10

70

Hence, option 2  is the correct answer.

The weight of Q is 5 kg, which is double the weight of P.
weight of P=5/2=2.5 kg
The weight of R is equal to the weight of P and Q taken together.
weight of R=5+2.5=7.5 kg
The weight of T is four times the weight of R.
weight of T=4*7.5=30 kg
The weight of S is half the weight of T.
weight of S=30/2=15 kg 

Hence, option (3) is the correct answer.

By checking option (1):

32 + 14 × 3 – 91 ÷ 7 = 3

After interchanging the signs,  (+ & -);

32 - 14 × 3 + 91 ÷ 7 = 3

or, 32 - 42 + 13 = 3

or, 3=3

So, it is correct option.

As, we found the correct answer, now we  no need to check more options.

Hence, option (1) is the correct answer.

72 + 63 ÷ 9 × 5 – 36 = 67

After interchanging the numbers (63 & 72) -

63 + 72 ÷ 9 × 5 – 36 = 67

 63 + 8 × 5 – 36 = 67

 63 + 40 – 36 = 67

 103 – 36 = 67

  67=67

So, it is correct option.

.Hence, option (2) is the correct answer.

These types of questions are solved by hit and trial method

So, choose 6 and 2

72 + 108 ÷ 9 – 11 × 6 = 18

Now apply BODMAS

72+12-11 × 6 = 18

72+12-66 =18

84-66= 18

18 =18

Hence, option (4) is the correct answer.

38 A 56 B 8 C 15 D (36 E 28) = 151

These types of questions are solved by hit and trial method

38-56÷8+15×(36-28)=151

Apply BODMAS

38-7+15×8=151

38-7+120=151

158-7=151

So, 151=151

Hence, option (2) is the correct answer.

42 ÷ 7 × 5 + 35 – 49 = 18

If the two numbers are interchanged of option (1) ,(42, 49) the equation becomes:
(1). 49 ÷ 7 × 5 + 35 – 42 = 18

-> On solving the L.H.S we get;
-> 7 × 5 + 35 – 42
-> 35 + 35 – 42 = 28
Not equal to R.H.S so it’s incorrect.

If the two numbers are interchanged of option (2) ,(35, 49) the equation becomes:

(2). 42 ÷ 7 × 5 + 49 – 35 = 18

-> On solving the L.H.S we get;
-> 6 × 5 + 49 – 35
-> 30 + 49 – 35 = 44
Not equal to R.H.S so it’s incorrect.

If the two numbers are interchanged of option (3) ,(5, 35) the equation becomes:

(3). 42 ÷ 7 × 35 + 5 – 49 = 18

-> On solving the L.H.S we get;
-> 6 × 35 + 5 – 49
-> 210 + 5 – 49 = 166
Not equal to R.H.S so it’s incorrect.

If the two numbers are interchanged of option (4) ,(42, 35) the equation becomes:

(4). 35 ÷ 7 × 5 + 42 – 49 = 18

-> On solving the L.H.S we get;
-> 5 × 5 + 42 – 49
-> 25 + 42 – 49 = 18
Which is equal to R.H.S so it’s correct.
Hence, option (4) is the correct answer.

As per the given information;

5 B 5 B 3 A 14 C (28 D 7) A 5 B (13 C 9)

After we put the given signs replacing the letters the equation becomes

5 × 5 × 3 + 14 - (28 ÷ 7) + 5 × (13 - 9)

75 + 14 – 4 + 5 × 4
75 + 10 + 20
 85 + 20 = 105

Hence, option (1) is the correct answer.

Given, there are equal number of coins of all types of denominations in the box.

Let, there are $x$ coins of all types of denominations.

According to the question:

$1x+5x+10x=1360$

Now, $16x=1360$

$x=85$

Hence, option (3) is correct.

On checking all the options one by one;

On interchanging the numbers (45, 9) in option (1),

9 ÷ 5 × 7 + 18 – 45 = 48

30.6 – 45 = 48 (False)

On interchanging the numbers (9, 7) in option (2),

45 ÷  5 × 9 + 18 – 7 = 48

       9 x 9 + 18 - 7 = 48

        81 + 18 - 7 = 48

        99 - 7 = 48

92 = 48 (False)

On interchanging the numbers (5, 9) in option (3),

45 ÷ 9 × 7 + 18 – 5 = 48

       5 x 7 + 18 - 5 = 48

        35 + 18 - 5 = 48

        53 - 5 = 48

48 = 48 (correct)

On interchanging the numbers (18, 9) in option (4),

45 ÷ 5 × 7 + 9 – 18 = 48

54 = 48 (False)

Hence, option (3) is the correct answer.

17 C 12 A (6 B 4) D 8 A 15 D 5

On the basis of given information when we place the signs in the given expression then;
⇒ 17 – 12 + (6 × 4) ÷ 8 + 15 ÷ 5
⇒ 17 – 12 + 24 ÷ 8 + 3
⇒ 17 – 12 + 3 + 3
⇒17 + 6 – 12

⇒23 – 12 = 11
Hence, option (3) is the correct answer.

$\mathrm{A}\to +,\mathrm{B}\to -,\mathrm{C}\to \times$

$\Rightarrow (7\mathrm{C}2)\mathrm{A}(3\mathrm{C}3)\mathrm{B}6$ 

$\Rightarrow (7\times 2)+(3\times 3)-6$

$\Rightarrow 14+9-6$

$\Rightarrow 17$

Hence option (1) is the correct answer.

This type of questions are solved by hit and trial method

On taking the equation of option (2);

12 + 3 × 2 – 4 = 10

Signs – and + are interchanged,

12 - 3 × 2 + 4 = 10

 Apply BODMAS

12-6+4=10

16-6=10

10=10

Hence, option (2) is the correct answer.

When we put the sign of option (4) in the equation, then;

Interchange – and +

8 - 6 × 4 ÷ 2 +10 = 6

Apply BODMAS

8-6×2+10=6

8-12+10=6

18-12=6

6=6

Hence, option (4) is the correct answer.

By checking option (1):

75  ÷ 15 – 18 × 12 + 17 = 259

After interchange:

78 ÷  18 – 15 + 12 × 17 = 259

Here, 78 is not exactly divisible by 18, so it will result in a decimal.

Hence, it is not the correct option.

By checking option (2):

75 ÷  15 – 18 × 12 + 17 = 259

After interchange:

57 17 × 18 - 12 + 15 = 259

Here, 57 is not exactly divisible by 17, so it will result in a decimal.

Hence, it is not the correct option.

By checking option (3):

75  ÷ 15 – 18 × 12 + 17 = 259

After interchange:

72 ÷ 12 × 18 - 15 + 17 = 259

Or, 6 × 18 +2 = 259

Or, 108 +2 = 259

or, 110=259

Hence, it is not the correct option.

By checking option (4):

75  ÷ 15 – 18 × 12 + 17 = 259

After interchange:

72 ÷ 12 + 18 × 15 - 17 = 259

Or, 6 + 270 - 17 =259

or, 259=259

Hence, it is the correct option.

Hence, option (4) is the correct answer.

By checking option (1):

8 – 13 + 32 ÷ 8 × 17 = 91

After interchanging the signs (+ , x)

8 – 13 × 32 ÷ 8 + 17 = 91

or, 8 – 13 × 4 + 17 = 91

or, 25 – 52 = 91

or, -27=91

so, it is not correct option.

By checking option (2):

8 – 13 + 32 ÷ 8 × 17 = 91

After interchanging the signs  ( - , x)

8 × 13 + 32 ÷ 8 - 17 = 91

or, 104 + 4 - 17 = 91

or, 108-17=91

or, 91=91

so, its correct option.

as, we found the correct answer, so no need to check more options.

Hence, option (2) is the correct answer.

After examining all the given options, we find that the equation given in option (4) will be true when the symbols are interchanged:

$18+3÷12\times 8=20$

Solving from the left, we get;

$18+2=20$

Thus,  LHS= RHS

Hence, option (4) is the correct answer.