Free Practice Questions for Mathematical-operation in Reasoning

${12}-{14}\times{21} ÷ {7}+{28}={193}$

After interchanging the place of$(\times)$ and $(-)$:

${12}\times{14}-{21} ÷ {7}+{28}={193}$

${12}\times{14}-{3}+{28}={193}$

${168}-{3}+{28}={193}$

${196}-{3}={193}$

${193}={193}$

LHS=RHS

Hence, option(1) is the correct answer.

36 A (15 C 4) B (21 A 13) A 24 D (16 D 2)

=${36}+{(15}\times{4)}-(21+13)+24\div(16\div2)$

=$36+60-34+3$

= 99 - 34

=$65$

Hence, option (3) is the correct answer.

Given,

5 - 24 + 17 × 16 ÷ 4 = 133

After interchanging $ {\times}$ with  - 

${5}\times{24}+{17} -{16} ÷ 4$= $133$

$120+17-4$= $133$

$137-4$= $133$

133 = 133

Hence, option (2) is the correct answer.

given,
$
A=+, B=\times, C=-, D=\div
$
After Applying all the signs in the given question

82 A 126 B 16 D 112 C 73

$=82+126 \times 16 \div 112-73$

$=82+126\times\frac{16}{112}-73$

$=82+126\times\frac{1}{7}-73$

$=82+18-73$

$=100-73$

$=27$

Hence, option (2) is the correct answer.

$\mathrm{A}$ (Denotes) $\longrightarrow+$ (addition)
$
\begin{aligned}
&\text { B (Denotes) } \rightarrow-(\text { subtraction) } \\
&\text { C (Denotes) } \rightarrow \times(\text { multiplication) } \\
&\text { D (Denotes) } \rightarrow \div \text { (division) } \\
&44 \text { A } 7 \text { B }(9 \text { C } 7) \text { A }(24 \text { B 19) A (18 D 6) C } 4 \\
&=44+7-(9 \times 7)+(24-19)+(18 \div 6) \times 4 \\
&=51-63+5+3 \times 4 \\
&=68-63 \\
&=5
\end{aligned}
$
Hence, option (2) is the correct answer.

Here;

The logic follows as:
(second number - first number) ${ }^2=$ third number

$(I I-I)^2=I I I$

$(10-5)^2=25$

Similarly,

$(15-9)^2=36$

Hence, option (3) is the correct answer.

Given:
$
3-36 \times 9 \div 3+12=3
$
On interchanging the signs $\div$ and $\times$ in the above equation
$
\begin{aligned}
&3-36 \div 9 \times 3+12 \\
&=3-4 \times 3+12 \\
&=3-12+12 \\
&=3
\end{aligned}
$
Hence, option (3) is the correct answer.

M  (Denotes)        →   $+$ (addition)

A  (Denotes)       →   $-$  (subtraction)

C  (Denotes  )      →  $\times$ (multipy)

B  (denotes)         →    $÷$   (Division)

25B5C5M5A6

$25÷5\times5+5-6$

$5\times5+5-6$

$25+5-6$

$30-6$

$24$

Hence, option (2) is the correct answer.

$P$ (Denotes) $\cdots+$ (addition)
$D$ (Denotes) $\cdots-$ (subtraction)
$S$ (Denotes) $\cdots \times$(multiplication)
$V$ (Denotes) $\cdots \div$ (Division)
5(7 S 3) D 3(8 P 6) V 7 D 11(3 S 13 S 2) P 2(41 S 9)
$5(7 \times 3)-3(8+6) \div 7-11(3 \times 13 \times 2)+2(41 \times 9)$
$5 \times 21-3(2)-11(78)+2(369)$
$105-6-858+738$
$843-864$
$-21$
Hence, option (1) is the correct answer.

Given-

$(11+5 \times 18)-8 \div 17$

On changing the value of the sign, according to the question

$(11-5+18) \div 8 \times 17$
$(11+18-5) \div 8 \times 17$
$
\begin{aligned}
&(29-5) \div 8 \times 17 \\
&24 \div 8 \times 17 \\
&3 \times 17=51
\end{aligned}
$
Hence, option (3) is the correct answer.

Given ;-
$
240 \times 20 \div 5+30
$
On changing the question marks in the above expression-
$
240-20+5 \times 30
$
$240-20+150$
$
390-20=370
$
Hence option (3) is the correct answer.

$
15 \times 6+132-11 \div 44=58
$
After interchanging the sign according to the question from option 3
$
\begin{aligned}
&15 \times 6+132 \div 11-44=58 \\
&90+12-44=58 \\
&102-44=58 \\
&58=58 \\
&\text { LHS }=\text { RHS }
\end{aligned}
$
Hence, option (3) is the correct answer.

$
45+35 \times 7-81 \div 9=321
$
After interchanging the positions of 45 and 81:
$
\begin{aligned}
&81+35 \times 7-45 \div 9=321 \\
&81+245-5=321 \\
&326-5=321 \\
&321=321 \\
&L H S=\text { RHS }
\end{aligned}
$
Hence, option (4) is the correct answer.

$
80-20+10 \div 8 \times 10
$
after interchanging the signs according to question,
$
\begin{aligned}
&=80 \div 20 \times 10-8+10 \\
&=4 \times 10-8+10 \\
&=40-8+10 \\
&=32+10 \\
&=42
\end{aligned}
$
Hence, option (1) is the correct answer.

Given equation:
$
15-14 \div 21 \times 27+9=64
$
After interchanging the signs according to question from option 1,
$
\begin{aligned}
&15-14+21 \times 27 \div 9=64 \\
&15-14+21 \times 3=64 \\
&1+63=64 \\
&64=64 \\
&L H S=\text { RHS }
\end{aligned}
$
Hence, option (1) is the correct answer.

 $106 \div 3 \times 2 + 70 - 7=110$

After interchanging the sign according to question:

$106 - 3 × 2 + 70 ÷ 7= 110$

$106 - 6 + 10 = 110$

100 + 10 = 110

110= 110

Here, LHS = RHS

Hence, option (2) is the correct answer.

$47+12 \div 288 \times 18$
After interchanging the sign according to question

$47 \times 12-288 \div 18$
$=47 \times 12-16$
$=564-16$
$=548$
Hence, option (4) is the correct answer.

Given

105 J 29 H 96 Y 16 D 84

$105-{29}\times{96}\div16+84$

= $105-29\times6+84$ 

= $105-174+84$
= $-69+84$

= $15$

Hence, option (4) is the correct answer.

$48 \times 5 + 9 \div 6 - (32 - 7) + 9$

After interchanging the sign and the values 

$48 \div 6 + 9 \times 5 - (32 - 7)+ 9$

= $8+ 45-(25)+9$

= $53-(25)+9$

= $28+9$

= $37$

Hence, option(3) is the correct answer.

As per given equation;

4 - 2 × 3 + 5 ÷1=10

After interchanging the signs of - and  ÷  in the given equation;

4  ÷ 2 × 3 + 5 -1=10

Apply BODMAS,

 2 × 3 + 5 - 1= 10

11 - 1 = 10

10  = 10

L.H.S = R.H.S

Hence, option (2) is the correct answer.