Free Practice Questions for Percentage in Maths

Let 

total number of votes $=100$%

According to Question

$\because 12\mathrm{\%}=9,600$ votes

Number of voters who did not participate in voting

$\therefore 15\mathrm{\%}=\frac{9,600}{12}\times 15=12,000$

$x\mathrm{\%}$ of $240$ = 60 $\mathrm{\%}$ of $(x+450)$

$\frac{x}{100}\times 240=\frac{60}{100}(x+450)$

$2.4x=0.6x+270$

$1.8x=270$

$x=150$

So $20\mathrm{\%}\times (150+50)=\frac{1}{5}\times 200=40$

and $40\mathrm{\%}\times 150=60$

So $40$ is $20$ less than $60$.

required $\mathrm{\%}=\frac{20\times 100}{60}\mathrm{\%}=33\frac{1}{3}\mathrm{\%}$

ATQ,

$\Rightarrow 40\mathrm{\%}+30=45\mathrm{\%}-40$

$\Rightarrow 5\mathrm{\%}=70$

$1\mathrm{\%}=14$

Total marks of exam $=100\times 14=1400$

Passing marks $=40\times 14+30=590$

$\therefore$ Percentage required to pass the exam = $\frac{590}{1400}\times 100$

$=42.15\mathrm{\%}$

Let the number of Votes =100%
Cast vote=60%
Not cast vote=40%
In cast vote two types
First type, Valid=75% $\times \frac{60}{100}$=45
Second, Invalid=60 - 45 = 15
BJP votes in % = 60%$\times \frac{45}{100}$=27
Looser looses by = 45 - 27 = 18%
Difference = 27%-18%=9%
9%=18000
$40\mathrm{\%}=\frac{18000\times 40}{9}=80000$

Let initial population of Aligarh $=x$

$\therefore x\times \frac{130}{100}\times \frac{75}{100}\times \frac{80}{100}=3,90,000$

$x=3,90,000\times \frac{100}{130}\times \frac{100}{75}\times \frac{100}{80}$$=5,00,000$

So, the  initial population of Aligarh is 5,00,000.

$20\mathrm{\%}\times 50\mathrm{\%}\times \mathrm{x}=2\times \mathrm{y}\times 25\mathrm{\%}\times 50\mathrm{\%}$
$\frac{20}{100}\times \frac{50}{100}\times x=2\times y\times \frac{25}{100}\times \frac{50}{100}$
$\frac{x}{10}=\frac{y}{4}$
$\frac{x}{y}=\frac{5}{2}$
$\mathrm{\%}=\frac{5-2}{2}\times 100=150\mathrm{\%}$

Let, income = 100, Saving = 35 and Expenditure = 65

New income = 100 +  $100\times \frac{20.1}{100}$ = 120.1

New expenditure = 65 + $65\times \frac{20}{100}$ =78

New savings = 120.1 – 78 = 42.1

Increase in saving = 42.1 – 35 = 7.1

Percentage =$\frac{7.1}{35}\times 100$= 20.3%

Price     ×         Sale     =        Revenue

10                     10        =        100

8                      (10+x) =        125

10 + x =  $\frac{125}{8}$

10+x = 15.625

x = 5.625 

Req % = $\frac{5.625}{10}\times 100$=56.25

$10\mathrm{\%}$ of 40 litres is 4 litres.

To make it $20\mathrm{\%}$ water.

you'll have to add ' $x$ ' litres of water to the mixture.

$\frac{x+4}{x+40}=\frac{20}{100}$

$x+4=(x+40)0.2$

$x+4=0.2x+8$

$0.8x=4$

$x=\frac{4}{0.8}$

$x=5$

$\begin{array}{ll}P& Q\\ \frac{5}{4}& \frac{4}{5}\end{array}$

$5-4=15kg$

$1=15kg$

$4=60kg$

Initial rate$=\frac{450}{60}$

$=Rs7.5perkg$

$69\mathrm{\%}$ of the candidates didn't cast their votes

$\mathrm{\%}$ of candidates cast their votes $=31\mathrm{\%}$

Out of $31\mathrm{\%}$, A received $11\mathrm{\%}$ votes, then $B$ receives $=20\mathrm{\%}$ votes

Value of $20\mathrm{\%}$ is equal to 145680

$20\mathrm{\%}=145680$

$\Rightarrow 1\mathrm{\%}=7284$

$\Rightarrow 100\mathrm{\%}=728400$

Hence, total % of votes that B received $=\frac{145680}{728400}=0.2\times 100=20\mathrm{\%}$

$A$ of $\frac{10}{100}=B$ of $\frac{30}{100}$

$\frac{A}{B}=\frac{3}{1}$

$C$ of $\frac{25}{100}=B$

$\frac{B}{C}=\frac{1}{4}$

$C=4$

$4=6000$

$1=1500$

$B=1500$

$A=3\times 1500=4500$

Hence,

$\mathrm{A}$ of  $60\mathrm{\%}$ + $\mathrm{B}$ of  $20\mathrm{\%}$ 

$\Rightarrow A\times \frac{60}{100}+B\times \frac{20}{100}$

$\Rightarrow 4500\times \frac{60}{100}+1500\times \frac{20}{100}$

$=2700+300$

$=3000$

Let Income of Aman is 100.

Income increase by = 37.5%

$25\mathrm{\%}=\frac{1}{4}$

So, $4\text{ unit }=5\times 4=20\mathrm{kg}$

Reduced price $=\frac{275}{20}=\frac{55}{4}=$₹ 13.75

Quantity of wheat of A quality $=\frac{40}{100}\times 60=24\mathrm{kg}$
Quantity of wheat of B quality $=60-24=36\mathrm{kg}$
Let a $\mathrm{kg}$ of wheat of A quality is added.
According to question
$\begin{array}{rl}& (24+36+a)\times \frac{40}{100}=36\\ & (60+a)=\frac{36\times 10}{4}=90\\ & a=90-60=30\mathrm{kg}\end{array}$

As per the question,
$11\mathrm{\%}=3190$
So , $100\mathrm{\%}=\frac{3190}{11}\times 100=29000$
29000 people went to see the matches in 2014.

Let total no. of votes be 1000 .
Votes which are valid $=1000-1000\times \frac{8}{100}=920$
Votes got by winning candidates $=920\times \frac{60}{100}=552$
Votes got by loosing candidates $=920-552=368$
Given, (552 - 368)unit $\to 5888$
184 unit $\to 5888$
1 unit $\to 32$
So, total votes registered $=1000\times 32=32000$

Passed students in section $1=80\mathrm{\%}$ of $40=32$
Passed students in section 2 $=76\mathrm{\%}$ of $50=38$
Passed students in section $3=64\mathrm{\%}$ of $50=32$
Passed students in section $4=65\mathrm{\%}$ of $60=39$
Passed students in section $5=70\mathrm{\%}$ of $60=42$
Total passed students $=183$
Total students $=260$
Pass students in percentage $=\frac{183}{260}\times 100\mathrm{\%}$
$=70.38\mathrm{\%}$

$\begin{array}{rl}\text{ Total marks }=& 100\mathrm{\%}\\ \text{ Marks scored }=& 390\\ \text{ Passing marks }=35\mathrm{\%}& =390+65\\ 35\mathrm{\%}& =455\\ 100\mathrm{\%}& =455\times \frac{100}{35}\end{array}$

Total marks of the examination $=1300$ 

Boys: Girls $=7:5$
Let boys are $=70x$
And girls are $=50x$
$60\mathrm{\%}$ of boys are below 14 years
Above 14 years boys $=40\mathrm{\%}$ of $70x$$=28x$
Above 14 years girls $=60\mathrm{\%}$ of $50x$$=30x$
Total students above 14 years $=870$
$28x+30x=870$
$58x=870$
$x=15$
$\begin{array}{rl}\text{ total number of students in the school }& =120x\\ & =120\times 15\\ & =1800\end{array}$