Practice questions here, for every subject and every exam. Unlimited questions for unlimited attempts, given with answers and explanations.
The seller had sold $30 \%$ of the oranges so now he has $70 \%(100-30)$ oranges left.
So, $70 \% \rightarrow 210$
$
\begin{aligned}
1 \% & \rightarrow 3 \\
100 \% & \rightarrow 300
\end{aligned}
$
$15 \%=\frac{3}{20}, \quad 12 \%=\frac{3}{25}$
When item is sold at a profit of $15 \%$
Selling price of item $=5,500 \times \frac{23}{20}=$₹ 6325
When another item is sold at a profit of $12 \%$
Selling price of item $=6325 \times \frac{28}{25}=$₹ 7084
Overall gain of yusuf $=7084-5500=$₹ 1584
Let 100 be the cost price of the article.
Market price $26 \%$ above the cost price $=100 \times \frac{126}{100}=$₹ 126
Selling price after $15 \%$ discount $=126 \times \frac{17}{20}=$₹ 107.1
$
\text { Gain } \begin{aligned}
\% &=\frac{126-107.1}{100} \times 100 \\
&=7.1 \%
\end{aligned}
$
Given, $S P=\frac{4}{3} C P$
$
\Rightarrow \frac{S P}{C P}=\frac{4}{3}
$
Profit $\%=\frac{4-3}{3} \times 100=\frac{100}{3} \%$
We know, 20% $=\frac{1}{5}, 5 \%=\frac{1}{20}$
Selling price when $20 \%$ discount is given $=3,200 \times \frac{4}{5}=$₹ 2560
Selling price when additional discount of $5 \%$ given $=2560 \times \frac{19}{20}=$₹ 2432
Sudha gains 30% by selling an article for ₹ 91. If she sells it for ₹ 78.75, then what will be her percentage loss/gain?
Cost price $=100 \% \quad$ profit $=30 \%$
Selling price $=$₹ 91
130% = ₹ 91
$100 \%=$₹ $91 \times \frac{100}{130}$
= ₹ 70
Cost price of article $=$₹ 70
Selling price $=$₹ 78.75
Profit $=$₹ 8.75
Profit $\%=\frac{ 8.75}{ 70} \times 100$
$\quad=12 \frac{1}{2} \%$
A sold an article to B at 24% profit. B sold it to C at 30% profit. If B's profit was ₹ 72.60 more than that of A, then how much (in ₹) did B pay for it?
Cost price of article for $\mathrm{A}=250 \mathrm{x}$
Selling price of article for $A=250 x+24 \%$ of $250 x$
$=310 x$
Cost price for $B=310 x$
Cost price for $\mathrm{C}=310 \mathrm{x}+30 \%$ of $310 \mathrm{x}$
$=403 x$
Profit of $A=60 x$
Profit of $B=93 x$
Difference of profit of $A$ and $B=$₹ 72.60
$33 x=$₹ 72.60
X = $\frac{ 72.60}{33}$
Cost price of article for B = 310x
$=310 \times \frac{ 72.60}{33}$
= 682
Total cost price of article = ₹ 6,800 + ₹ 700
= ₹ 7500
Marked price of article = ₹ 7500 + 8% of ₹ 7500
= ₹ 8100
Selling price of article = ₹ 6,196.50
₹$8100 \times \frac{90}{100} \times$$\frac{100-x}{100}=$₹ 6,196.50
$100-x=85$
$x=15 \%$
Let cost price of first Article $=40 \mathrm{x}$
Cost price of second article $=50 x$
Selling price of first article $=40 x+10 \%$ of $40 x$ $=44 x$
Selling price of second article $=50 x+20 \%$ of $50 x$ $=60 \mathrm{x}$
Difference of their selling price $=$₹ 480
$60 x-44 x=$₹ 480
$16 x=$₹ 480
$x=$₹ 30
Sum of cost price $=40 x+50 x$
$=90 x$
$=90 \times $₹ 30
$=$₹ 2700
Let marked price of article is $=100 x$
Then selling price $=80 \mathrm{x}$
Selling price $=120 \%$ of cost price because profit is $20 \%$
$80 \mathrm{x}=120 \%$ of cost price
Cost price $=80 x \times \frac{100}{120}=$₹ 448
$x=6.72$
Marked price $=100 \mathrm{x}$
$=$₹ 672
Let $\mathrm{CP}$ of Article $=100$ unit
After $13 \%$ discount SP will be $=120$ unit
120 unit $=87 \%$ of MP
MP of Article $=120$ unit $\times \frac{100}{87}$
In second case
If cost price increased by $10 \%$ then
$\mathrm{Cp}$ will be $=110$ unit
And profit is $20 \%$ then
$\mathrm{SP}=132$ unit
Then discount $\%$ is
$
\begin{aligned}
\text { MP }: \text { SP } &=120 \text { unit } \times \frac{100}{87}: 132 \text { unit } \\
&=957: 1000
\end{aligned}
$
Discount $\%=\frac{43}{1000} \times 100 \%$
$
=4.3 \%
$
A single discount equivalent to a series of successive discounts, 20%, 10% and 15%, is:
D1 = 20%
D2 = 10%
D3 = 15%
Overall discount percentage $=D 1+D 2+D 3-\frac{D 1 \times D 2+D 2 \times D 3+D 3 \times D 1}{100}-\frac{D 1 \times D 2 \times D 3}{10000}$
$=38.8 \%$
Let Cost price of the almirah for Amit $=x$
$x \times \frac{110}{100} \times \frac{110}{100}= 14,520 $
x= 12,000
Cost price for Amit =₹ 12,000
Total investment $=6$ chairs $\times $₹ 800+1 table $\times $₹ 1200
=₹ 6000
COST PRICE =₹ 6000
Selling price =₹ 7200
Profit =₹ 1200
Profit $\%=\frac{ 1200}{ 6000} \times 100 \%$
$=20 \%$
$
\begin{aligned}
&\text { Cost price }=7812 \\
&\text { Selling price }=6786 \\
&\begin{aligned}
\text { Loss } &=1026
\end{aligned} \\
&\begin{aligned}
\text { Loss } \% &=\frac{1026}{7812} \times 100 \% \\
&=13.13 \%
\end{aligned}
\end{aligned}
$
According to question
$
\begin{aligned}
&317.90=550 \times \frac{100-15}{100} \times \frac{100-x}{100} \times \frac{100-20}{100} \\
&317.90=550 \times \frac{85}{100} \times \frac{100-x}{100} \times \frac{80}{100} \\
&317.90=550 \times \frac{17}{20} \times \frac{100-x}{100} \times \frac{4}{5}
\end{aligned}
$
$374 x=37400-31790$
$374 x=5610$
$x=15$
Now, single discount $=2 \times \%=2 \times 15=30 \%$
New selling price $=550 \times \frac{100-30}{100}$
$=550 \times \frac{70}{100}=$₹ 385
Given, 2 unit = 450
1 unit = 225
The cost price of the article is = 1350 - 225 = ₹1125
When $C P$ of 12 pen is $=$₹ 100
Then $\mathrm{CP}$ of 60 pen is $=$₹ 500
When $\mathrm{CP}$ of 15 pen is $=$₹ 135
Then $\mathrm{CP}$ of 60 pen is $=$₹ 540
$\mathrm{CP}$ of total 120 pens $=500+540=1040$
SP of pens when it is sold at $20 \%=1040 \times \frac{120}{100}=1248$
SP of 1 pen $=\frac{1248}{120}=$₹ 10.4
Number of pen bought for $260=\frac{260}{10.4}=25$
A man bought two mobiles phones for ₹ 50,000. He sold one of them at a profit of 15% and the other at a loss of 20%. If the selling price of each mobile is the same, what is the approximate cost price (to the nearest rupee) of the mobile that was sold at a loss?
Let $\mathrm{x}$ and $\mathrm{y}$ be the cost price of first phone and second mobile respectively.
So, $x+y=50000$
According to question
$
\begin{aligned}
&\mathrm{x} \times \frac{115}{100}=\mathrm{y} \times \frac{80}{100} \\
&\frac{x}{y}=\frac{80}{115} \\
&\frac{x}{y}=\frac{16}{23}
\end{aligned}
$
Required cost price of mobile $=50000 \times \frac{23}{39}=29487$
Cost price when fan is bought at $18 \%$ discount $=2,600 \times \frac{82}{100}=$₹ 2132
Selling price when the same fan is sold at $15 \%$ discount $=2,800 \times \frac{85}{100}=$₹ 2380
He earns $=2380-2132=$₹ 248