Practice questions here, for every subject and every exam. Unlimited questions for unlimited attempts, given with answers and explanations.
As per the question,
Selling price of car $=$₹ 66000
So cost price of the car $=\frac{66000}{110} \times 100=$₹ 60000
If he sold 600 more than previous selling price,
New selling price $=66000+600=$₹ 66600
Now, Profit $\%=\frac{66600-60000}{60000} \times 100$
$
=\frac{6600}{600}=11 \%
$
A man sold a radio and a TV set together for ₹ 20,850, thereby making a profit of 20 % on the radio and 15 % on the TV set. If he had sold them together for ₹ 21,450, then he would have made 15 % profit on the radio and 20 % profit on the TV set. The cost price of the TV set was:
Let the cost price of radio is $100 x$ and the cost price of TV is $100 \mathrm{y}$
As per the question,
$120 x+115 y=20850$.............(i)
$115 x+120 y=21450$............ (ii)
Subtracting equation(i) from equation(ii)
$
5 y-5 x=600
$
$
y-x=120........(iii)
$
By adding equation (ii) and (i)
$
\begin{aligned}
&235 x+235 y=42300 \\
&x+y=180 \ldots \ldots \ldots \ldots . \ldots \text { (iv) }
\end{aligned}
$
Solving eq(iii) and eq(iv)
$
y=150 \text { and } x=30
$
So Cost price of TV set $=100 \times 150=$₹ 15000
A trader purchased a room cooler for ₹ 5,400 . After allowing a discount of 25%, he gains 25 %. What is the price marked on the room cooler ?
As per the question,
Cost price of cooler $=$₹ 5400
If he gets $25 \%$ profit then,
Selling price of cooler $=\frac{5400}{100} \times 125$ = ₹ 6750
If he gives $25 \%$ discount
Then, Marked price of cooler $=\frac{6750}{75} \times 100=$₹ 9000
The marked price of an article is ₹ 480 . After a discount of 18 % on the marked price, a shopkeeper earns a profit of ₹ 63.60. His percentage gain is:
Given,
Marked price of the article $=$₹ $480$
Selling price $=\frac{480}{100} \times 82=$₹ $393.6$
So, Cost price of the article $=$ Selling price $-$ Profit
$=393.6-63.6$
$=$₹ $330$
Profit $\%=\frac{63.6}{330} \times 100=19 \frac{3}{11} \%$
A student purchased a box of pencils at the rate of ₹ 35 for 10 pencils and sold all of them at the rate of ₹ 54 for 9 pencils. In this transaction, he gained ₹ 350. How many pencils did the box contain?
Let $x$ be the required pencils.
$
\begin{aligned}
&\frac{54 x}{9}-\frac{35 x}{10}=350 \\
&\frac{540 x-315 x}{90}=350 \\
&225x=350 \times 90 \\
&x=\frac{350 \times 90}{225}=140
\end{aligned}
$
A person lost 15 % by selling an item for ₹ 5,270. If he had sold the item for ₹ 6,324 , then what would his profit or loss percentage have been?
We know CP is $100 \%$.
So, $85 \% \Rightarrow 5,270$
$100 \% \Rightarrow 6,200$
$\mathrm{CP}=6200$
Required profit $=\frac{6,324-6200}{6200} \times 100=2 \%$
A dealer marked the price of an item 50 % above the cost price. He allowed three successive discounts of 10%, 15% and 20% to a particular customer. As a result, he incurred a loss of ₹ 410. At what price (in ₹) did he sell the item to the said customer?
Three successive discounts of 10%, 15% and 20% is given.
Now, dealer marked the price of an item 50 % above the cost price
(500-459)unit = 410
41 unit = 410
1 unit = 10
Required SP = 459 unit = 459×10 = 4590
An article was sold for ₹ 1,225 after allowing a discount of 12.5%. If 9.5 % discount is given, then for how much will it be sold?
$
12.5 \%=\frac{1}{8}
$
Market price $=1,225 \times \frac{8}{7}=$₹ $1,400$
Selling price $=1,400 \times \frac{100-9.5}{100}$
$
=14 \times 90.5=$₹ $1,267$
Arun Kumar bought 8 pieces of TV sets at ₹ 24,000 each and sold all 8 pieces at a total price of ₹ 2,26,560. What was his profit percentage or loss percentage?
CP for $8$ pieces of TV sets $=24,000 \times 8=$₹ $1,92,000$
Given, SP for $8$ pieces of TV set $=$₹ $2,26,560$
Profit $=2,26,560-1,92,000=$₹ $34560$
Profit $\%=\frac{34560}{192000} \times 100=18 \%$
For an item, a manufacturer gains 12 %, a wholesaler gains 10 %, and a retailer gains 15 %. Find the cost price of the item for the manufacturer, if its retail price is ₹ 56,672.
Let $x$ be the cost price of item,
According to question,
$
\begin{aligned}
&{x} \times \frac{112}{100} \times \frac{110}{100} \times \frac{115}{100}=56672 \\
&{x} \times \frac{28}{25} \times \frac{11}{10} \times \frac{23}{20}=56672 \\
&{x}=\frac{56672 \times 25 \times 10 \times 20}{28 \times 11 \times 23} \\
&{x}= 40000
\end{aligned}
$
Badri loses 15% when he sells his scooter for Rs. 17,000. At what price (in ₹), should he sell it to earn 18% profit?
Using formula
Badri should sell scooter for $=17,000 \times \frac{100}{85} \times \frac{118}{100}$
$
\begin{aligned}
&=17,000 \times \frac{20}{17} \times \frac{59}{50} \\
&=Rs.23,600
\end{aligned}
$
The cost of one chair is ₹ 450. Ravi buys 10 chairs for ₹ 3825. The discount per cent he gets in buying the 10 chairs is
CP of 10 chairs $=450 \times 10=4500$
SP of 10 chairs $=3825$
Required discount $=\frac{4500-3825}{4500} \times 100$
$
\begin{aligned}
&=\frac{675}{4500} \times 100 \\
&=15 \%
\end{aligned}
$
$
$
The cost price of an article is ₹ 1,545, which is 25 % below the marked price. If the article is sold at 18 % discount, what profit per cent is made on the transaction?
$\mathrm{CP}$ is $25 \%$ less than MP
So, $75 \%=1545$
$100 \%=2060$
$\mathrm{MP}=2060$
When Article is sold at $18 \%$ discount
$\mathrm{SP}=2060 \times \frac{82}{100}$
$=$ Rs. $1689.2$
Required profit $\%=\frac{1689.2-1545}{1545} \times 100$
$=9.33 \%$
He sold the item at $25 \%$ loss.
$
\begin{aligned}
\text {So,}75 \% &=870 \\
25 \% &=290 \\
100 \% &=1160
\end{aligned}
$
CP of article is Rs. 1160.
To earn the profit of $25 \%$
$
\mathrm{SP}=1160 \times \frac{125}{100}=\text { Rs. } 1450
$
Required cost of production of the table $=1100 \times \frac{100}{105} \times \frac{100}{110} \times \frac{100}{112}$
$
=850.34 \sim 850
$
$
25 \%=\frac{1}{4} \frac{\leftarrow \text { discount }}{\leftarrow \text { market price }}
$
We know, $\mathrm{SP}=3$ unit
3 unit $=614.25$
1 unit $=204.75$
4 unit $=819$
Required cost price $=819 \times \frac{100}{117}=700$
$\begin{aligned} \frac{C P}{M P}=& \frac{100-D \%}{100+P \%} \\=& \frac{100-20}{100+4} \\=& \frac{80}{104} \end{aligned}$
Required $\%=\frac{104-80}{80} \times 100$
$=\frac{24}{80} \times 100$
$=30 \%$
Single equivalent discount $=\left(a+b-\frac{a b}{100}\right) \%$
Single equivalent discount $5 \%$ and $10 \%$
$
\begin{aligned}
&\Rightarrow\left(5+10-\frac{5 \times 10}{100}\right) \% \\
&\Rightarrow(15-0.5) \%=14.5 \%
\end{aligned}
$
Single equivalent discount $14.5 \%$ and $16 \%$
$
\begin{aligned}
&\Rightarrow\left(14.5+16-\frac{14.5 \times 16}{100}\right) \% \\
&\Rightarrow(30.5-2.32) \%=28.18 \%
\end{aligned}
$
A shopkeeper marks his goods at 32 % above the cost price. He sells three-fifth of the goods at the marked price, one-fifth at a discount of 20 % on the market price, and the remaining at 40 % discount on the marked price. What is his profit/loss percentage?
Let cost price of goods be Rs. 100
Marked price of goods $=100 \times \frac{132}{100}=$ Rs. 132
Selling price when discount is $20 \%=132 \times \frac{80}{100}=$ Rs. $105.6$
Selling price when discount is $40 \%=132 \times \frac{60}{100}=$ Rs. $79.2$
Total selling price of goods $=3 \times 132+1 \times 105.6+1 \times 79.2=$ Rs. $116.16$
Profit % = $\frac{116.16-100}{100}\times{100}$ = 16.16 %
Cost price of the book for retailer $=312 \times \frac{100}{120}=$ Rs. 260
Cost price of the book for the wholesale dealer $=260 \times \frac{100}{125}=$ Rs. 208