Practice questions here, for every subject and every exam. Unlimited questions for unlimited attempts, given with answers and explanations.
A trader marked the price of an article so as to earn a profit of 28 % on its cost price. He sold it by giving a 15 % discount on its marked price. What was his actual profit percentage ?
Let the cost price be 100 units.
According to the question,
Marked price of the article $=100+100 \times \frac{28}{100}=128$ units
Then, selling price $=\frac{128}{100} \times 85=108.8$ units
Profit $\%=\frac{108.8-100}{100} \times 100=8.8 \%$
A shopkeeper sells an item for ₹ 1,638 after offering a discount of 16 % on its list price. Had he not offered any discount, he would have earned a profit of 30 %. What is the cost price (in ₹) of the article ?
Let the Marked price be 100 units .
As per the question,
Selling price $(84)=$₹ 1638
Marked price $=\frac{1638}{84} \times 100=$₹ 1950
He gets $30 \%$ profit at ₹ 1950 .
So, Cost price $=\frac{1950}{130} \times 100=$₹ 1500
Pens are bought by a shopkeeper at the rate of ₹ 1,200 for 150 pens and sold at the rate of ₹ 1,620 for 180 pens. His profit or loss per cent is:
As per the question ;
Cost price of 150 pens =₹ 1200
Cost price of 1 pen =₹ 8
Selling price of 180 pens =₹ 1620
Selling price of 1 pen $=\frac{1620}{180} \times 1=$ ₹ 9
Profit $\%=\frac{9-8}{8} \times 100=12.5 \%$
Let the cost price of the article be 100 units.
Initial Selling price $=100 \times \frac{88}{100}=88$ units
Increased selling price $=100 \times \frac{108.5}{100}=108.5$ units
Difference $(108.5-88)=164$
$20.5$ units $=164$
Then Cost price $=\frac{164}{20.5} \times 100=$₹ 800
An article was sold for ₹ 1,215 after giving a discount of 19%. If a discount of 17.5% is given, then for how much (in ₹) should the article be sold?
Selling Price $=$ Marked Price $\times \frac{(100-\text { Discount } \%)}{100}$
$1215=$ Marked Price $\times \frac{(100-19)}{100}$
Marked Price $=\frac{1215 \times 100}{81}=1500$
Now the discount is $17.5 \%$, So
New selling price $=1500 \times \frac{(100-17.5)}{100}=15 \times 82.5=$₹ 1237.5
After getting two successive discounts, Seema got a shirt at ₹ 153, for which the marked price was ₹ 200. If the second discount was 15%, the first discount was:
Selling Price $=$ Marked Price $\times \frac{(100-\text { Discount } \%)}{100}$
Let the first discount $\%$ is $x$, then
$
153=200 \times \frac{(100-x)}{100} \times \frac{(100-15)}{100}
$
$
\begin{aligned}
&100-x=\frac{153 \times 100}{2 \times 85}=90 \\
&x=10 \%
\end{aligned}
$
Jagat Singh sold an article for ₹ 6,000 and incurred a loss. Had he sold it for ₹ 7,400 , his profit would have been $\frac{2}{3}$ of the amount of loss that he incurred. At what price should he sell it to gain $25 \%$ profit?
Let the loss is $3 x$, then profit will be $2 x$.
According to question
$6000+3 x=7400-2 x$
$5 x=1400$
$x=$₹ 280
Cost Price $=6000+3 \times 280=6000+840=$₹ 6840
Required selling price $=6840 \times \frac{125}{100}=$₹ 8550
On selling an article for ₹ 984, Arun loses 18%. In order to gain 15%, he must sell it for:
Selling Price $=$ Cost Price $\times \frac{(100-\text { Loss })}{100}$
$984=$ Cost Price $\times \frac{(100-18)}{100}$
Cost Price $=\frac{98400}{82}=1200$
Required Selling Price $=1200 \times \frac{(100+15)}{100}=12 \times 115=$₹ 1380
A man sold 30 articles for ₹ 100 and gained 20%. The number of articles he bought for ₹ 100 was:
$
20 \%=\frac{1}{5}
$
Price $\propto \frac{1}{\text { Quantity }}$
According to question
$5 \rightarrow 30$ articles
$1 \rightarrow 6$ articles
So, $6 \rightarrow 36$ articles
A man sells two articles at ₹ 9,180 each. He gains 8 % on one article and loses 15 % on the other. His overall profit or loss is:
$
8 \%=\frac{8}{100} \quad, 15 \%=\frac{15}{100}
$
As per the question,
$\mathrm{CP}$ of article sold at $8 \%$ Profit $=\frac{9180}{108} \times 100=8500$
$\mathrm{CP}$ of article sold at $15 \%$ Loss $=\frac{9180}{85} \times 100=10800$
So, total cost price =₹ $19300$
Total selling price $=9180 \times 2=$₹ $18360$
Loss $=19300-18360=$₹ $940$
A shopkeeper has some toys. He sells two-third of the toys at a profit of 35 % and the remaining toys at 10 % loss. What is his overall percentage of profit ?
Let the shopkeeper has 3 toys.
As per the question,
He sells 2 article at $35 \%$ profit and the remaining at $10 \%$ loss
So, Total profit $/$ loss $=2 \times 35+1 \times(-10)$
$
=60 \%
$
Overall Profit $=\frac{60}{3}=20 \%$
Let the Marked price of first article is $x$ and Marked price of another article is $y$.
As per the question,
$20 \%$ of $x=25 \%$ of $y$
$
\frac{x}{y}=\frac{5}{4}
$
So, the ratio of marked price of the first article and second article is $5: 4$ and it is not the exact value of the marked price.
By going through the option, only option 3rd satisfies the ratio between them.
Let the marked price of the article be 100 units.
As per the question,
Selling price after $20 \%$ discount $=\frac{100}{100} \times 80=80$ units
80 units $=$₹ 120
So, 100 units(Marked price) $=\frac{120}{80} \times 100=$₹ 150
If the article has been sold at 150 then there is $20 \%$ profit.
i.e. $120 \%=$₹ 150
$100 \%=\frac{150}{120} \times 100=$₹ 125
So cost price of the article $=$₹ 125
A dealer sold an article at a loss of 4 %. Had he sold it for ₹ 120 more, he would have gained 8 %. To gain 11 %, he should sell the article for ?
Let the Cost price of the article $=100$ units
As per the question,
Selling price of the article $=100 \times \frac{96}{100}=96$ units
Selling price if he gets $8 \%$ profit $=100 \times \frac{108}{100}=108$ units
So $(108-96)$ units =₹ 120
12 units =₹ 120
Cost price of the article $=\frac{120}{12} \times 100=$₹ 1000
Selling price for the gain of $11 \%=\frac{1000}{100} \times 111=$₹ 1110
A shopkeeper marks his products 40% above their cost price. He sells 60% of the products at the marked price and the remaining at 65% discount on the marked price. His gain/loss in the whole transaction is:
Let the the number of products is $5$ and cost price of each is $100 x$, then
Marked Price $=\frac{140}{100} \times 100 x=140 x$
When $3$ products were sold at marked price,
Profit $\%=\frac{140 x-100 x}{100 x} \times 100=40 \%$
And when $2$ products were sold at $65 \%$ discount,
Selling Price of each $=140 x \times \frac{35}{100}=49 x$
Loss $\%=\frac{100 x-49 x}{100 x} \times 100=51 \%$
Overall gain $/$ loss $=\frac{3 \times 40 \%-2 \times 51 \%}{5}=\frac{120 \%-102 \%}{5}=\frac{18 \%}{5}=3.6 \%$
As the value is positive, So there will be gain.
Hence, Gain of $3.6 \%$
By selling an item for ₹ 3,750 a shopkeeper earned 25% profit. If the item had been sold for ₹ 300 more, then what would have been the profit percentage of the shopkeeper?
Selling Price $=$ Cost Price $\times \frac{(100+\text { Profit })}{100}$
$3750=$ Cost Price $\times \frac{(100+25)}{100}$
Cost Price $=\frac{3750 \times 4}{5}=$₹ $3000$
Now it was sold at ₹ $3750 + 300$ = ₹ $4050$
Hence, Profit $\%=\frac{4050-3000}{3000} \times 100=\frac{1050}{30}=35 \%$
A dealer allows his customers a discount of 20% and still gains 20%. If the cost price of an article is ₹ 960, what is its marked price (in ₹)?
Selling Price $=$ Cost Price $\times \frac{(100+\text { Profit })}{100}$
Selling Price $=960 \times \frac{(100+20)}{100}=96 \times 12=144 \times 8$
Selling Price $=$ Marked Price $\times \frac{(100-\text { Discount })}{100}$
$144 \times 8=$ Marked Price $\times \frac{(100-20)}{100}$
Marked Price $=\frac{144 \times 8 \times 10}{8}=$₹ 1440
A shopkeeper bought an item for ₹ 4,500 and sold it at a loss of 5%. From this money, he bought another item and sold it at a profit of 10%. What is his overall profit?
Cost price of the new item $=$ Selling price of the old item
Cost price of the new item $=4500 \times \frac{(100-5)}{100}=4500 \times \frac{19}{20}=$₹ $4275$
Selling price of the new item $=4275 \times \frac{(100+10)}{100}=4275 \times \frac{11}{10}=$₹ $4702.5$
Overall profit $=4702.5-4500=$₹ $202.5$
$21 \times C P=15 \times S P$
$\frac{C P}{S P}=\frac{15}{21}=\frac{5}{7}$
Profit $\%=\frac{7-5}{5} \times 100=\frac{200}{5}=40 \%$
A shopkeeper bought 200 notebooks at the rate of ₹ 80 for 5 . He sold half of them at the cost price and the remaining notebooks at the rate of ₹ 100 for 5 . What is his profit percentage ?
As per the question,
He bought 5 notebook for ₹ 80 then,
His total cost price for 200 notebook $=80 \times 40$
His total selling price for 200 notebook $=80 \times 20+100 \times 20$
$=20 \times(180)$
His total profit by selling 200 notebook $=20 \times 180-80 \times 40$
$
=400
$
Profit $\%=\frac{400}{3200} \times 100=12.5 \%$